Common Calculus Problems Explained

First principles, cubic sketches and optimisation — the three calculus question types you'll definitely see in NSC Paper 1.

· 6 min read · Snap&Learn

First principles

Keep the limit notation on every line. Drop it and you drop marks.

Cubic graph sketches

Find f'(x) = 0 for stationary points; use f''(x) to classify; find intercepts.

First principles, worked

For f(x) = 2x² − 1: f(x + h) − f(x) = 4xh + 2h². Dividing by h gives 4x + 2h, and letting h → 0 gives f′(x) = 4x.

A cubic, worked

For f(x) = x³ − 3x² − 9x + 5: f′(x) = 3x² − 6x − 9 = 3(x − 3)(x + 1), so the stationary points are at x = 3 and x = −1. f(3) = −22 is a local minimum and f(−1) = 10 is a local maximum. The point of inflection is halfway between them, at x = 1.

Rate of change, worked

If s(t) = 2t³ − 3t² metres, the velocity is s′(t) = 6t² − 6t, so at t = 2 seconds it is 6(4) − 6(2) = 12 m/s.

Tangents to a curve

A tangent question gives a curve and an x-value (or a gradient). The derivative gives the gradient, the original function gives the point, and y − y₁ = m(x − x₁) gives the line. Example: for f(x) = x³ − 2x at x = 1, f(1) = −1 and f′(x) = 3x² − 2, so m = f′(1) = 1 and the tangent is y = x − 2.

Optimisation, worked

An open box is made from a 12 cm × 12 cm square of cardboard by cutting a square of side x from each corner and folding up the sides. Its volume is V(x) = x(12 − 2x)². Then V′(x) = (12 − 2x)² − 4x(12 − 2x) = (12 − 2x)(12 − 6x). V′(x) = 0 gives x = 6, which makes a box with no base, so reject it, or x = 2. The maximum volume is V(2) = 2 × 8² = 128 cm³.

Reading a graph of f′(x)

  • Where f′(x) = 0, f has a stationary point.
  • Where f′(x) > 0, f is increasing; where f′(x) < 0, f is decreasing.
  • For a cubic f, the graph of f′ is a parabola, and its turning point gives the x-coordinate of f's point of inflection.
  • f is concave up where f″(x) > 0 and concave down where f″(x) < 0.

A checklist for every calculus question

  • Rewrite roots and fractions as powers of x before differentiating.
  • Use correct notation: f′(x) =, dy/dx = or Dₓ[…].
  • Substitute into f(x), not f′(x), to find y-coordinates.
  • State the nature of every stationary point, with a reason.

Optimisation

Always two equations: the quantity to maximise/minimise and a constraint. Substitute, differentiate, set to zero. When a question stops you, snap it into Snap&Learn — you'll get a CAPS-aligned step-by-step explanation in seconds, and your first three AI solutions are free.

Frequently asked questions

How many marks is calculus worth in Paper 1?

Around 30–35 marks out of 150.

What is the difference between f′(x) = 0 and f″(x) = 0?

f′(x) = 0 gives the x-coordinates of the stationary points. f″(x) = 0 gives the x-coordinate of the point of inflection, where the concavity changes.

Do I need to show that an optimisation answer is a maximum?

Yes. Show that the second derivative is negative for a maximum (positive for a minimum), or test the sign of the first derivative on either side, and reject values that do not fit the context.

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