Differential Calculus

Calculus covers first principles, rules of differentiation, equations of tangents, stationary points, points of inflection, and optimisation problems.

Calculus covers first principles, rules of differentiation, equations of tangents, stationary points, points of inflection, and optimisation problems.

Key concepts

  • First principles: f'(x) = lim_{h→0} [f(x+h) − f(x)] / h
  • Power rule: d/dx[xⁿ] = n·xⁿ⁻¹
  • Tangent at x = a has gradient f'(a)
  • Stationary points: f'(x) = 0
  • Concavity: f''(x)

How it works

Differentiate using the rule (almost always the power rule in Matric). Set f'(x) = 0 to find stationary points; use f''(x) or a sign table to classify them. For optimisation, write the quantity to optimise as a function of one variable, differentiate, and solve f'(x) = 0.

Step by step

1. Differentiate

Use the power rule term by term.

2. Solve f'(x) = 0

Find x-values of stationary points.

3. Classify

Use f''(x) or sign analysis.

4. Interpret

State coordinates and nature of each point.

Worked examples

Find the stationary points of f(x) = x³ − 3x.

  1. f'(x) = 3x² − 3
  2. 0 = 3x² − 3 → x = ±1
  3. f(1) = −2; f(−1) = 2

Answer: (1, −2) local min; (−1, 2) local max

Find the equation of the tangent to f(x) = x² − 3x at x = 1

  1. f(1) = 1 − 3 = −2, so the point is (1; −2)
  2. f′(x) = 2x − 3, so the gradient is f′(1) = −1
  3. y − (−2) = −1(x − 1)

Answer: y = −x − 1

A rectangle has a perimeter of 60 cm. Find the dimensions that give the maximum area.

  1. Constraint: 2x + 2y = 60, so y = 30 − x
  2. Area A = x(30 − x) = 30x − x²
  3. A′(x) = 30 − 2x = 0, so x = 15
  4. A″(x) = −2 < 0, so this is a maximum

Answer: 15 cm by 15 cm, an area of 225 cm²

Use first principles to find f′(x) if f(x) = −x²

  1. f(x + h) − f(x) = −(x + h)² + x² = −2xh − h²
  2. Divide by h: −2x − h
  3. Take the limit as h → 0

Answer: f′(x) = −2x

Common mistakes

  • Forgetting to bring down constants when differentiating
  • Mixing up local max and min
  • Not writing the equation of the tangent in y = mx + c form
  • Forgetting to check that a stationary point is a maximum (or minimum) in optimisation

Frequently asked questions

Is first principles tested every year?

Yes — usually a 4–6 mark question early in Paper 1.

What does the second derivative tell me?

f″(x) gives the concavity. At a stationary point, f″(x) < 0 means a local maximum and f″(x) > 0 means a local minimum.

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