Sketch and interpret parabolas, hyperbolas, exponentials and logs for NSC Paper 1. CAPS-aligned examples plus AI step-by-step explanations.
Functions is one of the highest-mark sections in Paper 1. You need to sketch, interpret, find intersections, average gradient and inverses across parabolas, hyperbolas, exponential and logarithmic graphs. In Grade 12 the focus moves to inverse functions: you find the equation of an inverse, sketch a function and its inverse on the same axes, and decide whether the inverse is a function. Questions usually give a sketch with a few labelled points, and you use them to find the unknown values of a, p and q before answering the rest of the question.
Complete the square: (x − 2)² − 9. Turning point is (2, −9).
Swap x and y: x = 3ʸ, so y = log₃ x. f⁻¹(x) = log₃ x, with domain x > 0 (the range of f becomes the domain of the inverse).
Asymptotes: x = 1 and y = 3. y-intercept: g(0) = 2/(−1) + 3 = 1, so (0, 1). x-intercept: 2/(x − 1) = −3, so x − 1 = −2/3 and x = 1/3, giving (1/3, 0).
f(1) = −8 and f(4) = −5. Average gradient = (f(4) − f(1)) / (4 − 1) = (−5 + 8) / 3 = 1.
Swap x and y: x = 2y², so y² = x/2 and y = √(x/2). Take the positive root because the restricted domain x ≥ 0 of f becomes the range y ≥ 0 of the inverse.
Usually one full question on the inverse of an exponential or quadratic — domain restrictions, sketches and 'is the inverse a function?'.
The inverse undoes the function: the x- and y-values swap, so the graph is reflected in the line y = x. The domain of the function becomes the range of the inverse.
A parabola is many-to-one, so its reflection fails the vertical line test. Restricting y = ax² to x ≥ 0 or x ≤ 0 makes it one-to-one, so the inverse is a function.
Straight lines, parabolas, hyperbolas, exponential graphs and their inverses (including logarithmic graphs), and cubic graphs in the calculus section. Trigonometric graphs are examined in Paper 2.
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