Grade 11 analytical geometry: equation of a straight line, angle of inclination, parallel and perpendicular lines, and properties of shapes, with worked…
Analytical geometry is about 30 of the 150 marks in Grade 11 Paper 2. You still use the Grade 10 distance, midpoint and gradient formulas, and add the equation of a straight line and its angle of inclination, tan θ = m.
Typical questions give the vertices of a triangle or quadrilateral and ask you to find equations of sides, medians and altitudes, the angle between two lines, or to prove what kind of shape it is. Grade 12 extends this to the equation of a circle and tangents.
tan θ = 1, so θ = 45°.
Parallel lines have equal gradients, so m = 4. y − 3 = 4(x − 2), so y = 4x − 5.
Perpendicular gradients multiply to −1, so m = −½. The line passes through the origin, so c = 0: y = −½x.
tan θ = −1. The reference angle is 45°, and a negative gradient means an obtuse inclination: θ = 180° − 45° = 135°.
The angle a line makes with the positive x-axis, measured anticlockwise. It is between 0° and 180°, and tan θ equals the gradient.
Find each line's angle of inclination, then subtract the smaller from the larger (using the exterior angle of the triangle the lines form with the x-axis).
No. Circles and tangents in analytical geometry are Grade 12 work.
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