Grade 11 measurement: surface area and volume of pyramids, cones, spheres and composite objects, and the effect of scaling, with worked CAPS examples.
Grade 11 measurement revises the surface area and volume of prisms, cylinders, pyramids, cones and spheres, and applies them to composite objects such as a cone on a hemisphere or a cylinder with a hollow inside. It is examined with Euclidean geometry in Paper 2.
The formulas are given, so the marks are for choosing the right ones, working out missing lengths (often with Pythagoras), and keeping track of which faces are included. You also use scale factors: multiplying every length by k multiplies area by k² and volume by k³.
V = ⅓πr²h = ⅓ × π × 9 × 4 = 12π cm³.
Slant height s = √(3² + 4²) = 5 cm. Total surface area = πr² + πrs = 9π + 15π = 24π cm².
Total surface area = 2πr² + 2πrh = 50π + 100π = 150π cm².
Hemisphere: ½ × (4/3)π(3)³ = 18π. Cone: ⅓π(3)²(4) = 12π. Total = 30π ≈ 94.25 cm³.
Yes, the formulas for surface area and volume are normally provided. You need to know which one to use and how to find missing lengths.
The distance from the apex to the edge of the base, along the surface. Find it with Pythagoras: s² = r² + h².
Add the areas of the exposed surfaces only. Faces where two solids are joined are inside the object, so leave them out.
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