Grade 9 Theorem of Pythagoras: finding the hypotenuse or a shorter side, testing for right-angled triangles, and real-world word problems, with examples.
The Theorem of Pythagoras says that in a right-angled triangle, the square of the hypotenuse equals the sum of the squares of the other two sides: c² = a² + b². The hypotenuse is always the longest side, opposite the right angle.
In Grade 9 you use the theorem to find a missing side, to test whether a triangle has a right angle, and to solve problems such as ladders against walls or the diagonal of a screen. It's used constantly in Grades 10 to 12, in trigonometry, analytical geometry and measurement.
The ladder is the hypotenuse. h² = 5² − 3² = 25 − 9 = 16, so h = 4 m.
d² = 9² + 12² = 81 + 144 = 225, so d = 15 cm.
Test the longest side: 9² = 81, but 6² + 7² = 36 + 49 = 85. Since 81 ≠ 85, it is not right-angled.
d² = 80² + 60² = 6 400 + 3 600 = 10 000, so d = 100 cm.
Subtract, because the hypotenuse is known: a² = 13² − 5² = 169 − 25 = 144, so a = 12 cm.
No, only right-angled triangles. For other triangles you'll use the sine and cosine rules in Grade 11.
Three whole numbers that fit c² = a² + b², such as 3; 4; 5, 6; 8; 10 and 5; 12; 13.
Add the squares when you're finding the hypotenuse (the longest side). Subtract when you know the hypotenuse and need a shorter side.
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